Post by wafisher on Jan 6, 2006 14:14:28 GMT -5
Two- Dimensional Motion
59 d = 1/2gt^2 d = 5 (4^2) = 5(16) = 80 meters
60 d = vt (in x-direction) so d = 22(9) = about 200 meters
61 .25 seconds using g = 9.8
62 constant! it doesn't change if we ignore air friction
63 a = v^2 / r a = 100(100)/25 = 400 m/s/s
64 Torque is Force x distance, in this case 25 x 4 = 100 Newtons
65 find speed by taking distance divided by time
for distance use 2pi (r). for time calculate the number of seconds in a year
Universal Gravitation
66 use F = Gm1m2/r^2
67
68 okay to skip!
69 Cavendish
70 third
71 slower
72 increases
73 G = 6.67 x 10E-11
74 decreases
75 ellipses
59 d = 1/2gt^2 d = 5 (4^2) = 5(16) = 80 meters
60 d = vt (in x-direction) so d = 22(9) = about 200 meters
61 .25 seconds using g = 9.8
62 constant! it doesn't change if we ignore air friction
63 a = v^2 / r a = 100(100)/25 = 400 m/s/s
64 Torque is Force x distance, in this case 25 x 4 = 100 Newtons
65 find speed by taking distance divided by time
for distance use 2pi (r). for time calculate the number of seconds in a year
Universal Gravitation
66 use F = Gm1m2/r^2
67
68 okay to skip!
69 Cavendish
70 third
71 slower
72 increases
73 G = 6.67 x 10E-11
74 decreases
75 ellipses